Chemistry, asked by amohimin10p6redj, 1 year ago

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Answers

Answered by limelight1726

Heya mate
The answer of ur question is

QUESTION

4.6 g of ethyl alcohol mixed with 6g of acetic acid.Find out the value of Kc if 2g of acetic acid remains unused in chemical reaction.

As we know that the , Equilibrium constant is the ratio of the product.

Given Equation is here

C2H5OH + CH3COOH->> CH3COOC2H5 + H2O

KC = frac of [H2O]×[CH3COOC2H5][CH3COOH]×[C2H5OH]

KC=2/3×2/3

=4/9

KC =0.44

hope you got it

Answered by Anonymous

Refer to the attachment!!

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