Please find the angle asked
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technicalboyak:
How can we consider ac as diameter
Some things are not given in the question. You have to assume it.
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Your answer is 50°
Step-by-step explanation:
Given : ∠AGC = 50°
→ In ΔACG
→ ∠ACG = 90° [∵EG is tangent]
→ ∠ACG + ∠AGC + ∠CAG = 180°
→ 90° + 50° + ∠CAG = 180°
→ ∠CAG = 180° - 140° ⇒ 40°
Now, In ΔABC
→ ∠CAB + ∠ABC + ∠BCA = 180°
→ 40° + 90° + ∠ACB = 180°
→ ∠ACB = 180° - 130° ⇒ 50°
Please mark my answer as Brainliest
Why abc 90°
angle on semi circle
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