Question

nor ! 5) A bag contains 5 red beads, 6 blue beads, 3 yellow beads and 6 green beads. What is the probability of choosing (i) a blue or a yellow bead (ii) a red bead on the first draw and a green bead on the next if the first bead is replaced in the bag before the second is drawn (iii) a blue bead on the first draw and a red bead in the next, with the first one not being replaced.​

Answer 1

Answer:(1) for choosing a blue or yellow bead will be 9/20

(2)5/20 for a red bead and for a green bead in the given situation will be 6/20

(3)for the blue bead the probability will be 6/20  and for the red bead in the given situation will be 5/19

Answer 2

Answer:

P(choosing a blue bead) = 6/20=3/10

P(choosing yellow bead) = 3/20

P(blue U yellow)

= P(blue) + P(yellow)

=3/10 + 3/20

=6+3/20

=9/20

Answer:: 9/20