Question

Nora leaves town a and walks towards town b at a speed of 100 m/min. At the same time, Kate and Lixin walk from town b towards town a at a speed of 80 m/min and 75 m/min respectively. If Nora meets Lixin 6 minutes after passing Kate, find the distance between Town a bad town b

Answer 1

name as Steven Melvin

Steven left Town A and walked towards Town B at a speed of 100m/min. At the same time, Jason and Melvin started from Town B and walked towards Town A at a speed of 80m/min and 75m/min respectively. If Steven met Melvin six minutes after passing Jason, find the distance between Town A and Town B.
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Steven ----- 100m/min
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Jason--------80m/min
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Melvin-------75m/min
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Let distance between towns be x m 
Steven ----- 100m/min
Jason--------80m/min
combined speed = 180 m.min
Time taken = x/180 minutes.
... 
Steven ----- 100m/min
Melvin-------75m/min
combine speed = 175 m/min
..
Time = x/175
...
Difference in time of meeting = 6 minutes.
x/175 - x/180 = 6 
(180x-175x)/175*180=6
5x=175*180*6
5x=189,000
/5 
x= 37,800 meters
OR 37.8 km
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