Question

Normality of 0.04M h2so404M h2so4

Answer 1

0.08N

Normality = Molarity × N-Factor

Here the N-Factor is 2.

Since, H2S04 gives out 2 H.

Answer 2

Normality of 0.04 M sulphuric acid can be found as 0.08 N.

Finding the Normality

To find the normality of the given solution we have to find the product of the given molarity and the N-factor.

N- factor is nothing but the number of hydrogen atoms in the given substance.

Here sulphuric acid has 2- H atoms.

Normality = molarity x N-factor

                $= 0.04\times 2\\=0.08 N$

So the normality of the given acid is 0.08N .