Chemistry, asked by kriti2401, 1 year ago

normality of solution containing 35g of KOH dissolved in sufficient water to make 400ml solution

Answers

Answered by chelsy02
11
normality=
 \frac{35}{56}  \times 1 \times  \frac{1000}{400}  \\  =  \frac{5}{8}  \times 1 \times  \frac{5}{2}  \\  =  \frac{25}{16}  \\
Answered by arshikhan8123
1

Concept:

Normality:

It is used to define the concentration of the particular solution. Normality is defined as the ratio of number of gram equivalents to the volume of the solution in liters.

It is expressed as:

Normality= Number of gram equivalents/Volume of the solvent in liters

Given:

Mass of  KOH = 35 g

Volume of solution = 400 ml

Molar mass of KOH= 56 g/mol

Gram equivalent = 35/56= 0.625 g/eq

Find:

Normality of the solution=?

Solution:

Calculation for Normality:

The normality of the given solution can be calculated as follows:

Normality= Number of gram equivalents/Volume of the solvent in liters

N= (0.625*1000 )/400

N=0.156 N

Thus, the normality of the solution is 1.56 N.

#SPJ3

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