Question

Northe gas. Q. No. 18 Calculate the energy radiated in one minute by black body of surface area 200 em at 127°C (o = 5.7 x 10-8 m 's-K-4​

Answer 1

Answer:

1740 J

Explanation:

From the Steffan Bolzmann law:

Power dissipated by black body P =

Since it is a black body = 1

Temperature T = 273+ 127 = 400 K

Also o = 5.67*10-³ J/m²sK4

Therefore, P = 200*10-4 * 1 * 5.67*10-³ * 400 = 29 J/s

We know that Energy = power*time

Energy = 29 J/s * 60 s = 1740 J

Hope it helps =)