Science, asked by Nidhitr, 1 year ago

note on %of oleum and %of so3 in oleum.

Answers

Answered by Brainlytrainer
3
▪️◾️◼️ Answer -


% of oleum and % of so3 in oleum.

oleum is a mixture of h2so4 and so3 is obtained in contact process for the synthesis of h2so4 . when oleum is diluted with water , so3 present in the mixture is converted into h2so4. in this way the amount of h2so4 obtained from the given amount of oleum is more than the amount of oleum taken due to addition of water to from h2so4. if 100 g sample of oleum forms 118g h2so4 %g oleum is said to be 118 % and 18g of H2O reacts with So3 present in oleum . with eh help of above information , we can calculate the amount of so3 present in 100g sample of given oleum . e.g , in 118 % oleum 18g water reacts with so3 according to the given reaction to form h2so4.


reaction :-

SO3 + H2O -------------> H2SO4.

1 MOL 1 MOL. 0
0. 0. 1 mole


18 g h20 , reacts with 80g ( mol ) of so3 thus, in the above sample of oleum , 100 g oleum contains 80g s03 or % of so3 =80.


=============================================

BE BRAINLY
Answered by ElegantSplendor
8

Answer:

The acute health effects of sulfuric acid (H2SO4), sulfur trioxide (SO3), and oleum are discussed in one TSD because sulfur trioxide and oleum will eventually be converted into sulfuric acid. Oleum (fuming sulfuric acid) is a mixture of sulfuric acid with up to 80% free sulfur trioxide.

Similar questions