Math, asked by TGSUJEET, 28 days ago

Now, (2x ^ 2 + x - 5)(x ^ 2 - 2x + 3)​

Answers

Answered by ZaraAntisera
0

Answer:

\mathrm{Expand\:\left(2x^2+x-5\right)\left(x^2-2x+3\right):\quad 2x^4-3x^3-x^2+13x-15}

Step-by-step explanation:

\mathrm{\left(2x^2+x-5\right)\left(x^2-2x+3\right)}

\mathrm{Apply\:the\:distributive\:law:\quad \left(a+b\right)\left(x+y+z\right)=ax+ay+az+bx+by+bz}

\mathrm{\left(2x^2+x-5\right)\left(x^2-2x+3\right)=}

\mathrm{2x^2x^2+2x^2\left(-2x\right)+2x^2\cdot \:3+xx^2+x\left(-2x\right)+x\cdot \:3-5x^2-5\left(-2x\right)-5\cdot\ 3}

\mathrm{=2x^2x^2+2x^2\left(-2x\right)+2x^2\cdot \:3+xx^2+x\left(-2x\right)+x\cdot \:3-5x^2-5\left(-2x\right)-5\cdot \:3}

\mathrm{=2x^4-3x^3-x^2+13x-15}

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