Question

Now last question a body moving with velocity 10 m/s, experience a retardation of 4 m/s². Find the distance travelled in 3 seconds.​

Answer 1

Answer:

Explanation:

Where v is 10 m/s,

Retardation is 4 m/s^2,

Time is 3 seconds.

v-u/t=retardation,

10-u/3=4,

10-u=4*3,

10-u=12,

-u=12-10,

-u=2,

So 10-2,

8 m is the distance travelled.

I think it is correct.

Hope it helps you.

Answer 2

Explanation:

Given that:-

(Final velocity) v = 10m/s

(Initial velocity) u= 0m/s

Retardation = 4m/s²

Time = 3 seconds

( Distance)s = ?

From second equation of motion:-

Now, S = ut+½at²

= 0× 3 + ½×-4×(3)²

= 0 + ½×-4×9

= 0-18

= 18 m