now what is my next step
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it is wrong
please
cheach the answer
please
cheach the answer
swapnil67:
the question is findt the zeroes of quadratic polynomial and verify the relationship the zeroes and cofficiant
yeah
so solve this pls
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2x^2 + 18x + 40=0
for solving a quadratic equation,
first multiply the coeffecient of x^2 and the given constant number.
here 2*40=80
the u should split the product you have got into two terms
in that manner when u add the splitened numbers you should get the coeffecient of the term x.
here if u split 80 into 8*10, if u add them u r getting 18
so, 2x^2+8x+10x+40=0
take the common terms,
2x(x+4)+10(x+4)=0
(2x+10)(x+4)=0
hence 2x+10=0 and x+4=0
2x=-10 x=-4
x=-5
the zeros of coeffecients are x=-4 and x=-5
for solving a quadratic equation,
first multiply the coeffecient of x^2 and the given constant number.
here 2*40=80
the u should split the product you have got into two terms
in that manner when u add the splitened numbers you should get the coeffecient of the term x.
here if u split 80 into 8*10, if u add them u r getting 18
so, 2x^2+8x+10x+40=0
take the common terms,
2x(x+4)+10(x+4)=0
(2x+10)(x+4)=0
hence 2x+10=0 and x+4=0
2x=-10 x=-4
x=-5
the zeros of coeffecients are x=-4 and x=-5
thanks shruthi
no need yaar...if u are clear then thats enough
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