ns has 2 as a root? (A) x² – 4x + 5 = 0 (B) x² + 3x – 12 = 0 (C) 2x² – 7x + 6 = 0 (D) 3x² – 6x – 2 = 0
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Step-by-step explanation:
Substituting x=2 in given equations
A:
x
2
+4x−5⇒(2
2
)+4×2−5⇒4+8−5=7
B:
x
2
+3x+12⇒(2
2
)+3×2+12⇒4+6+12=22
C:
2x
2
−7x+6⇒2(2
2
)−7×2+6⇒8−14+6=0
D:
3x
2
−6x+2⇒3(2
2
)−6×2+2⇒12−12+2=2
Then (C) equation has 2 as a root.
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