Math, asked by aarushi3113, 11 months ago

nth derivative of log(ax+x^2)


ParthThakre9965: witg respect to x?
aarushi3113: yes
ParthThakre9965: nth?
ParthThakre9965: or only one?
aarushi3113: nth derivative...
ParthThakre9965: because after a point it will become one.......
ParthThakre9965: then I don't know........
aarushi3113: kks...

Answers

Answered by nuuk
19

solution:

=log(ax+x^2)

dy/dx = 1/(ax + b ) x a = a/ (ax +b)

d^2y/dx^2 = -1/(ax + b) x a x a = - a^2/(ax +b)^2

d^3 / dx^3  = 2a^3/(ax + b )^3 = (-1) ^3+1 x 2a^3/(ax +b)^3

in general

d^ny/dx^n = (-1)^n+1 x (n-1)a^n/(ax + b)^n


Answered by mamtabrijesh
2

Answer:

log(ax+x^2)

dy/dx = 1/(ax + b ) x a = a/ (ax +b)

d^2y/dx^2 = -1/(ax + b) x a x a = - a^2/(ax +b)^2

d^3 / dx^3 = 2a^3/(ax + b )^3 = (-1) ^3+1 x 2a^3/(ax +b)^3

in general

d^ny/dx^n = (-1)^n+1 x (n-1)a^n/(ax + b)^n

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