nth derivative of log(ax+x^2)
ParthThakre9965:
witg respect to x?
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solution:
=log(ax+x^2)
dy/dx = 1/(ax + b ) x a = a/ (ax +b)
d^2y/dx^2 = -1/(ax + b) x a x a = - a^2/(ax +b)^2
d^3 / dx^3 = 2a^3/(ax + b )^3 = (-1) ^3+1 x 2a^3/(ax +b)^3
in general
d^ny/dx^n = (-1)^n+1 x (n-1)a^n/(ax + b)^n
Answered by
2
Answer:
log(ax+x^2)
dy/dx = 1/(ax + b ) x a = a/ (ax +b)
d^2y/dx^2 = -1/(ax + b) x a x a = - a^2/(ax +b)^2
d^3 / dx^3 = 2a^3/(ax + b )^3 = (-1) ^3+1 x 2a^3/(ax +b)^3
in general
d^ny/dx^n = (-1)^n+1 x (n-1)a^n/(ax + b)^n
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