Question

nth term of an arithmetic sequence is 4n+1. what is the first term
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Answer 1

Step-by-step explanation:

Nth term of given A.P. (Arithmetic Progression) is 4n+1.

So, first term = 4(1)+1 =5

Second term= 4(2)+1=9

Third term= 4(3)+1=13

……

Thus, the A.P. is 5,9,13….

And the common difference is 9–5=13–9=4

Alternatively, if nth term is 4n+1

and (n+1)the term is 4(n+1)+1= 4n+4+1=4n+5

Then, common difference=(4n+5)-(4n+1)=4n+5–4n-1=4

Thus, common difference=4