(ntse exam question) A number is selected at random from fi33/4
rst 50 natural numbers. The probability that selected number is a multiple of 3 or 4 is:
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Q: A number is selected at random from first 50 natural numbers. The probability that selected number is a multiple of 3 or 4 is:
A:
number of multiples of 3 below 50 = 50/3 = 16 (ignore the remainder)
number of multiples of 4 below 50 = 50/4 = 12 (ignore the remainder)
Common multiples of 3 and 4 = multiples of 12
number of multiples of 12 below 50 = 50/12 = 4
(these are the ones we have counted both for 3 and 4, so it needs to be subtracted once)
So total multiples of 3 or 4 below 50 = 16+12 -4 = 24
Probability = 24/50 = 12/25
A:
number of multiples of 3 below 50 = 50/3 = 16 (ignore the remainder)
number of multiples of 4 below 50 = 50/4 = 12 (ignore the remainder)
Common multiples of 3 and 4 = multiples of 12
number of multiples of 12 below 50 = 50/12 = 4
(these are the ones we have counted both for 3 and 4, so it needs to be subtracted once)
So total multiples of 3 or 4 below 50 = 16+12 -4 = 24
Probability = 24/50 = 12/25
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