Chemistry, asked by jxRaalpander, 1 year ago

NTSE Sample Question Chemistry A burner consumes one gram of LPG in 11 sec. What is the power of consumption of burner in KW if Cv of LPG is 55 kJ/g. (a) 5 kW (b) 10 kW (c) 5.5 kW (d) None of these

Answers

Answered by lifeislife
1
The answer is, a). 5 kW.
It is because, we all know that, Power=work/time
or Power=E/time= 55(given value)/11
which is equal to, 5.
Hope this will help you.
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