Nucleus of an iron atomhas a radius of 4×10 powerminus 15m and coating 26 proton. what is repulsive electrostatic force acts between two proton in such a nucleus.
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Answer:
plz brainliest
Explanation:
We may use Coulomb's Law in electrostatics to find the force of repulsion (since like charges repel) between these 2 electric point charges, each having the unit quantity of charge equal to the charge of 1 electron,
1.6
×
10
−
19
C
.
F
=
k
Q
1
Q
2
r
2
, where
k
=
9
×
10
9
N
.
m
2
/
k
g
2
is Coulomb's constant.
∴
F
=
(
9
×
10
9
)
×
(
1.6
×
10
−
19
)
2
(
3.8
×
10
−
15
)
2
=
15.956
N
.
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