Math, asked by sumantpareek80, 7 months ago

Numbaer of boys and girls in a class in the ratio 7:5 . The number of boys is 8 more than the number of girls . Then find the total class strength

Answers

Answered by Harpreet0059
0

Answer:

Let, The number of boys = 7x and the number of girls =5x.

According to the condition,

7x = 5x + 8

2x = 8

x = 4

Therefore The number of boys = 7x = 7 × 4 = 28 and the number of girls =5x = 5 × 4 = 20.

Therefore total strength of the class = 28 + 20 = 48

Answered by akhileshkumarsimri
0

Answer:

48

Step-by-step explanation:

let the common number in both is x

then

the number of boys=7x

and the number of girls=5x

acording to the question ,

5x+8=7x7×4=28

and the number of girls=5×4=20

so the total class strength=28+20=48

8=7x-5x

8=2x

2x=8

x=8/2

x=4

so the number of boys=

Similar questions