Number 3 to 17 are put into a box. find the probability of getting a number : a) grater than 6, b) less than or equal to 17, c) odd
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number of total possible outcomes=( 3 to 17)
=15
1)number of favourable outcomes= (greater than 6)= 11
p(greater than 6)=11/15
2)number of favourable outcomes=(less than or equal to 17)= 15
p(greater than or equal to 17) =15/15= 1
3) number of favourable outcomes=(odd ,3,5,7,9,11,13,15,17)= 8
p(odd)= 8/15
=15
1)number of favourable outcomes= (greater than 6)= 11
p(greater than 6)=11/15
2)number of favourable outcomes=(less than or equal to 17)= 15
p(greater than or equal to 17) =15/15= 1
3) number of favourable outcomes=(odd ,3,5,7,9,11,13,15,17)= 8
p(odd)= 8/15
Reyansh11:
thanks sir
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