Question

number 34A is exactly divisible by 2 and leaves a remainder I, when divided by 5,
bd 2 leaves the remainders
find A.​

Answer 1

Answer:

A is 6 and the number is 346.

Step-by-step explanation:

For a number exactly divisible by 2 the unit place of the number should be divisible by 2.

So by trail and error method number ending with 2,4&6 are divisible by 2.but it should be divided by 5 to get a reminder 1.

so if number is 6 or A is 6 then the number will be 346 which is divisible by 2 and also by 5 remainder gives 1.

Hence A=6.and the number 346.