Math, asked by shuklasanjay11111111, 2 months ago

Number 3X10000 + 0X1000 +8X100 +OX lot7
da is equal to which of the following
(@) 303084' (b) 30,807 c) 3,807
.

Answers

Answered by singhprince0457

Answer:

(b) 30,807

Step-by-step explanation:

Given : 3x10000+0x1000+8x100+0x10+7x1

To find : Equal number

Solution:

3x10000+0x1000+8x100+0x10+7x1

One's place = 7

Ten's place = 0

Hundred's Place = 8

Thousand's Place = 0

Ten Thousand's place = 3

Hence Number = 30807

3x10000+0x1000+8x100+0x10+7x1 = 30807

3x10000+0x1000+8x100+0x10+7x1

= 30000 + 0 + 800 + 0 + 7

= 30000 + 800 + 7

= 30000 + 807

= 30807

3x10000+0x1000+8x100+0x10+7x1 = 30807

Answered by madukasundi157

Answer:

Answer is (b.) 30,807.

Don't forget to thanks

Mark as brainlist.

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Number 3X10000 + 0X1000 +8X100 +OX lot7da is equal to which of the following(@) 303084' (b) 30,807 c) 3,807.​

Answers

Answer is (b.) 30,807.

Don't forget to thanks

Mark as brainlist.

Number 3X10000 + 0X1000 +8X100 +OX lot7
da is equal to which of the following
(@) 303084' (b) 30,807 c) 3,807
.