number 6n can not end with(where n is a natural number)
Answers
Answered by
1
Answer:
Let us on the contrary assume that 6^n can end with a digit 0.
But, 6 = 2¹×3¹
It cannot be expressed in the form 2^x×5^y,
where x,y>0.
Therefore, 6^n cannot end with a digit 0.
THAT'S YOUR ANSWER↑
BTW, ARE YOU IN 10th?
Similar questions