Question

number lock has 9 different digits. A combination of three digits can be set to open the lock. How many combinations are possible if the digits cannot be repeated? A 168 B 42 C 84 D 504

Answer 1

Answer:

D.504

Step-by-step explanation:

we can calculate the number of probable combinations by=9*8*7=504

Answer 2

Step-by-step explanation:

Given number lock has 9 different digits. A combination of three digits can be set to open the lock. How many combinations are possible if the digits cannot be repeated?

•  So the number lock has 9 different digits.
• So it has total 9 possibilities each time.
• So if it is three times then 9 x 9 x 9 = 729 different possibilities.
• There are 9^3 = 729 different ways if there are repetitions
• If there are no repetitions then we have 9 x 8 x 7 = 504 ways
• Therefore if the digits cannot be repeated 504 ways are possible.

Reference link will be

https://brainly.in/question/43926488