Number of 3 digit odd numbers by using digits 123456
Answers
Answered by
0
1. Without Repetition.
Possible digits as those at unit place: 1, 3, 5.
When each among these is taken as at unit place, the other 5 numbers are arranged at tens and hundreds places in 5P2 = 20 ways.
So the answer is 20 × 3 = 60.
2. With repetition.
Even when each digits among 1, 3 and 5 are selected as at unit place, the all 6 numbers are arranged at tens and hundreds places in 6² = 36 ways.
So the answer is 36 × 3 = 108.
Hope this helps. Plz mark it as the brainliest.
Plz ask me if you have any doubts.
Thank you. :-))
Similar questions