Question

NUMBER OF ARRANGEMENTS THAT CAN BE MADE BY TAKING ALL FROM 5 BLACK BALLS AND 3 RED BALLS OF SAME SIZE

Answer 1

5 BLACK BALLS & 3 RED BALLS So, add 5 black balls and 3 red balls ( given that arrangements are madr by taking both coloured balls) 5+3= 8 and 5 black balls repeated and 3 red balls repeated. so, 8! /3!×5! = 40,320/ 720 = 56. No arrangements are 56