number of atoms present in 22.4 litre of helium at ntp
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Vol. of helium gas at ntp= no. of moles x 22.4
no of moles = vol. of gas / 22.4
no. of moles = 22.4/22.4 = 1 mole
Now, no. atoms = 1 x 6.022 x 10*23 atoms
Here the ans.
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no of moles = vol. of gas / 22.4
no. of moles = 22.4/22.4 = 1 mole
Now, no. atoms = 1 x 6.022 x 10*23 atoms
Here the ans.
I hope it may help u
mark it in brialenlist
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