Question

Number of atoms present in 56ml O2 at STP

Answer 1

1 mol of O2 = 6.02 X 10^23 molecules = 22.4L

No. of atoms = 2 x 6.02 x 10^23 = 22.4L = 22400ml

1ml = 2 x 6.02 x 10^23 / 22400 atoms

56ml = 2 x 6.02 x 10^23 x 56 / 22400 = 3.01 x 10^21 atoms