Number of atoms present in 9.0g of aluminium. Calculate.
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refer to the pic
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atomic mass of aluminium=27u
avagadro no. =molar mass
6.022×10 power 23=27g of al
1g oct al=6.022×10२३÷27
=2.673×10२३
avagadro no. =molar mass
6.022×10 power 23=27g of al
1g oct al=6.022×10२३÷27
=2.673×10२३
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