Question

number of diagnolas in a polygon having 10 sides is

Answer 1

Remember, this formula works for a polygon of any number of sides greater than 3. Hexagon (6 sides): n(n-3)/2 = 6(6-3)/2 = 6*3/2 = 18/2 = 9 diagonals. Decagon (10 sides): n(n-3)/2 = 10(10-3)/2 = 10*7/2 = 70/2 = 35 diagonals. Icosagon (20 sides): n(n-3)/2 = 20(20-3)/2 = 20*17/2 = 340/2 = 170 diagonals..

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Answer 2

Hey dude,
Your answer is
THE NUMBER OF DIAGNOLS IN A POLYGON HAVING 10 SIDES {DECAGON} IS 35.
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