number of distinct prime factors of largest 5 digit number is
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Number of distinct prime factors of the largest 4 digit number.
Largest 4 digit number = 99999
Prime Factorization of 99999= 3 x 3 x 41 x 271
Distinct prime factors of 99999 = 3^2,41,271
Therefore, the total number of distinct prime factors of 99999 is 3 (i.e. 3, 41 and 271).
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Answer:
99999 because 99999 ×1
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