Question

Number of electron present in 18 g of water is

Answer 1

Dear student
Here we will use the the concept of density of water = 1g/cc
D=M/V
1 g/ml = M/18 ml
M= 18 g
moles of water = mass/molar mass = 18/18 = 1
1 mole of water contains = NA molecules
total electrons in water = 2(H) + 8(O) = 10
1 molecule of water contains = 10 electrons
1 mole water contains = 10 * NA electrons
NA = Avogadro’s number