number of electrons in 32g ch4 pls answer
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Answer:
12.0468*10^24 electrons
Explanation:
gram molecular mass of methane=12+4=16g
=>1 mole of methane weighs 16 g
=>32g of methane contains 2 moles of methane
2 moles of methane - 2*6.023 * 10^23 molecules
1 molecule of methane has 6+4=10 electrons
=>6.023*2*10^23 molecules = 2 moles= 32 g of methane contains 6.023*2*10^23*10== 12.0468*10^24 electrons
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