Question

number of electrons present in C(C N)_{4}C(CN)4​ is​

Answer 1

Answer:

the carbon atom contains 4 electrons.

Explanation:

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Answer 2

The no of electrons present in C(CN)₄ molecule is 58.

- The no of electrons present in 1 carbon atom = 6

- The no of electrons present in 1 nitrogen atom = 7

- The no of electrons present in 1 cyanide molecule = No of electrons in 1 carbon atom + No of electrons in 1 nitrogen atom

⇒The no of electrons present in 1 cyanide molecule = 6 +7 = 13

- Total no of electrons in C(CN)₄ molecule = No of electrons in 1 carbon atom + No of electrons in 4 cyanide molecules

⇒ C(CN)₄ = 6 + 4 × 13

⇒ C(CN)₄ = 6 + 52 = 58 electrons.