number of fe atoms in 100 g haemoglobin if it contains 0.33% fe
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% of fe= 0.33 of molecular weigh of haemoglobin
therefore .
weight of fe present = (0.33/100)*67200
= 221.76
atomic mass of fe = 56
no.of approx. atom present = 221.76/56
=3.96 (approx 4)
hence, here are 4 fe molecule in one haemoglobin molecule
hope its helps u .... :)
therefore .
weight of fe present = (0.33/100)*67200
= 221.76
atomic mass of fe = 56
no.of approx. atom present = 221.76/56
=3.96 (approx 4)
hence, here are 4 fe molecule in one haemoglobin molecule
hope its helps u .... :)
nimmi3:
thanq.. :)
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