Number of Fe atoms in 100gm haemoglobin if it contains 0.33% Fe...?
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Answer:
Answer is 3.54 × 10²¹
Explanation:
Weight of Hemoglobin = 100g ∵ Hemoglobin contains 0.33% of Fe ∴ weight of Fe in hemoglobin = 0.33% of 100g = 0.33/100 × 100 = 0.33g Atomic weight of Fe = 56g/mol Weight of Fe = 0.33g ∴ number of mole = weight of Fe/atomic weight of Fe = 0.33/56 = 0.00589 ∵ number of atoms = number of mole × Avogadro's number∴ number of atoms of Fe = 0.00589 × 6.023 × 10²³ = 0.0354 × 10²³ = 3.54 × 10²¹ Hence, answer is 3.54 × 10²¹
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