Question

Number of g of oxygen in 32.2g Na2SO4.10H2O is 1) 20.8 2) 224 3) 22.4 4) 2.08 Plzzz give me the solution as early as possible......

Answer 1

No. of oxygen atoms in one molecule =4+10=14
Thus moles of oxygen in n moles of compound=n*14
Molar mass of Na2SO4.10H2O=46+32+64+180=322g/mol

Thus
 $32.2g=32.2/322=0.1 mols$ 

Thus moles of O=$0.1*14=1.4$
So weight is 

$16*1.4=22.4g$

Answer 2

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Hope it is help to u.