Question

Number of HCL molecules present in 10 ml of 0.1 N of HCL solution is

Answer 1

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Answer 2

0.1 N solution
Normality = Molarity × n factor
0.1 =molarity × 1
molarity =0.1
thus 1 litre will cintain 0.1 moles
that is 1000 ml contaim 0.1 moles
thus 100 ml contain 0.01
and 10 ml contain 0.001 moles

now
no. of molecules =0.001 ×6.022×10^23
no. of molecules = 6. 022× 10 ^20


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