Chemistry, asked by DeepakTiwari2789, 8 months ago

Number of isomeric alcohols of molecular formula C₆H₁₄O
which give positive iodoform test is [NEET Kar. 2013]
(a) two (b) three
(c) four (d) five

Answers

Answered by Fatimakincsem
0

The number of isomeric alcohols of molecular formula C₆H₁₄O  which give positive iodoform test is four.

Option (C) is correct.

Explanation:

The iodoform test is positive for alcohols with formula R - CHOH - CH3. Among C6H14O isomers, the ones with positive iodoform test are:

(1) CH3 - CH2 - CH2 - CH3 - CHOH - CH3.

(2) CH3 - CH2 - CH(CH3) - CHOH - CH3

(3) (CH3)2 CH - CH2 - CHOH - CH3

(4) (CH3)3C - CHOH - CH3

Thus the number of isomeric alcohols of molecular formula C₆H₁₄O

which give positive iodoform test is four.

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