Number of isomeric alcohols of molecular formula C₆H₁₄O
which give positive iodoform test is [NEET Kar. 2013]
(a) two (b) three
(c) four (d) five
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The number of isomeric alcohols of molecular formula C₆H₁₄O which give positive iodoform test is four.
Option (C) is correct.
Explanation:
The iodoform test is positive for alcohols with formula R - CHOH - CH3. Among C6H14O isomers, the ones with positive iodoform test are:
(1) CH3 - CH2 - CH2 - CH3 - CHOH - CH3.
(2) CH3 - CH2 - CH(CH3) - CHOH - CH3
(3) (CH3)2 CH - CH2 - CHOH - CH3
(4) (CH3)3C - CHOH - CH3
Thus the number of isomeric alcohols of molecular formula C₆H₁₄O
which give positive iodoform test is four.
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