Question

Number of maximum possible electrons in Zn for which n+l =4, is_____???​

Answer 1

Answer:

Given,

n + l = 4

where,

l = angular momentum quantum number

n = Principle quantum number

From Energy level of electrons we know,

l ≤ n - 1

Satisfying this condition,

The values of n and l will be 3,1 and 4,0 respectively.

Now:

Case I:

n = 3

l = 1

so, here these represents 3p subshell.

Hence, maximum no. of electrons = 6

Case II:

n = 4

l = 0

so, here these represents 4s subshell.

Hence, maximum no. of electrons = 2.

Therefore, from case I and II:

Total no. of electrons = 6 + 2 = 8

We know,

Electrons with same pin = 8 / 2 = 4.

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Answer 2

The number of maximum possible electrons in Zn for which n+l = 4 is EIGHT (8).

- The electronic configuation of Zn is 1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 3d10.

- The value of l for s, p and d are 0, 1 and 2 respectively.

- For (n+l) = 4, only two combinations for n and l are possible, n = 4 , l = 0 and n = 3 , l = 1.

- These subshells are 4s and 3p respectively.

- 4s can accomodate a maximum of 2 electrons and 3p can accomodate a maximum of 6 electrons.

- So, the maximum possible electrons possible for Zn with (n+l) becomes (2+6) = 8.