Number of milli moles of solute present
in 40 me of 0.2m solution
08
8
2 200 3 25 . 40
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Answer:
Molarity (M) : The number of moles of a solute dissolved in 1 L (1000 ml) of the solution is known as the molarity of the solution.
Molarity of a solution
(M)=
molar mass of solute
mass of solute
×
volume of solution in mL
1000
∴0.2=
40
w
×
500
1000
so w=4gm.
Amount of sodium hydroxide present in 500ml of 0.2M solutions is 4 gm.
Explanation:
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