Question

Number of milli moles of solute present
in 40 me of 0.2m solution
08
8
2 200 3 25 . 40​

Answer 1

Answer:

Molarity (M) : The number of moles of a solute dissolved in 1 L (1000 ml) of the solution is known as the molarity of the solution.

Molarity of a solution

(M)=  

molar mass of solute

mass of solute

​  

×  

volume of solution in mL

1000

​  

 

∴0.2=  

40

w

​  

×  

500

1000

​  

 

so w=4gm.

Amount of sodium hydroxide present in 500ml of 0.2M solutions is 4 gm.

Explanation: