Question

number of molecules present in 28 gram of nitrogen atoms are
(1)de 2.9.3 moles (c) 0.5 mode.cd). 2 moles​

Answer 1

By Avagadro's law, 1 Nitrogen mole or 28 g of Nitrogen contains 6.023 x 10^23 no. of molecules. Nitrogen, being a diatomic element, the no. of atoms = 2 x 6.023 x 10^23 atoms.

Answer 2

Answer:

0.5 ithink is correct answer