Question

NUMBER OF MOLES FOR 100 G OF kmN04

Answer 1

Given:-

→Mass of KMnO₄ = 100g

To find:-

→ Number of moles present in 100g

of KMnO₄

Solution:-

In KMnO₄ (Potassium Permanganate), three elements are present i.e Potassium (K) , Manganese (Mn) and Oxygen (O).

• Atomic mass of Potassium (K) = 39u

• Atomic mass of Manganese (Mn) = 54u

• Atomic mass of Oxygen (O) = 16u

Thus, molecular mass of KMnO₄:-

= 39+54+16×4

= 93+64

= 157u

We know that molar mass of a compound, is the molecular mass in grams. Thus, molar mass of KMnO₄

is 157g.

Number of moles = Given mass/Molar mass

= 100/157

= 0.63 mole. [approximately]

Thus, 0.63 moles are there in 100g of KMnO₄.