Question

Number of moles of C obtained on reacting 20 moles of A with excess B by reaction:
2A+B =3C
If% yield of reaction is 80%?
a. 20 moles
b.24 moles
c.30 moles
d.40 moles
please answer fast..​

Answer 1

Answer:

d. 40 moles

Explanation:

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Answer 2

Answer:

2A + B ---> 3C

Since excess B is taken , we will consider A to be the limiting reagent.

Now since 20 moles of A are taken , let us assume all 20 moles reacted (100% yield) and formed C.

According to stoichiometry and comparing the coefficients of balanced equation:

2 moles of A form 3 moles of C

20 moles of A form 30 moles of C

Assuming 100% theoretical yield , 30 moles of C are formed.

But given % yield is 80%

So actual moles of C obtained = 80% of 30 = 24 moles of C

Ans is b. 24 moles

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