Question

Number of moles of kmno4 required to oxidize one mole of fec2o4 in acidic medium is

Answer 1

Final Answer :3/5 mole

Understanding :
1) Law of Equivalents.
2) n factor

Steps:
1) Predict the change in Oxidation state of compounds in reactants.
2) Use law of equivalents.

Answer 2

Given:

$KMnO_4$ reacts with $FeC_2O_4$ in acidic medium.

To find:

Number of moles of $KMnO_4$ required to oxidize one mole of $FeC_2O_4$ in acidic medium = ?

Calculation:

• When $KMnO_4$ reacts in acidic medium, it accepts 5 electrons.
• Likewise in acidic medium $FeC_2O_4$ looses 3 electron (Ferrous ion looses one electron and oxalate ion looses 2 electron).
• Thus the n factor of $KMnO_4$ and $FeC_2O_4$ are identified as 5 and 3 respectively.

• The number of equivalent of $KMnO_4$ is equal to number of equivalent of $FeC_2O_4$.
• $n\times5=3\times1$
• $n=\frac{3\times1}{5} = \frac{3}{5} = 0.6 moles$

Conclusion:

Thus it can be inferred that 0.6 moles of $KMnO_4$ is required to oxidize one mole of $FeC_2O_4$ in acidic medium.

Learn more about such concept

What is mole? how it is calculated???

https://brainly.in/question/3247765

The ratio of number of moles of KMnO4 and K2Cr2O7 required to oxidise 0.1 mole Sn+2 to Sn+4 in acidic medium

https://brainly.in/question/5811054