Question

Number of moles of oxygen atoms present in 360 mg of glucos

Answer 1

Heya user !!!

Here's the answer you are looking for

The molar mass of glucose or C6H12O6 is 180g

So 180g = 1mole

360mg = 360 × 10^ -3 g = 2 × 10^-3 moles

Now, in each glucose molecule there are 6 oxygen atoms. 

So in 2 × 10^-3 moles of glucose, moles of oxygen 
= 2 × 10^-3 moles × 6 
= 12 × 10^-3 moles 
= 0.012 moles


Therefore, there are 0.012 moles of oxygen atoms in 360 mg of glucose.



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