number of moles of oxygen present in 0.3 moles of ozone . ???
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Answered by
16
Given, no. of moles of ozone = 0.3
Mass of the ozone = 0.3 × 48
= 14.4 g.
Now, Let us first calculate the total no. of atoms in 0.3 mole of ozone.
No. of atoms of O = 3 × 0.3 × 6.022 × 10^23
= 3 × 1.81 × 10^23 atoms.
Now, 3 × 1.81 × 10^23 atoms of oxygen are present in 0.3 moles of Ozone.
Using the formula,
No. Of atoms = No. of moles × Avogadro's number
Thus,
No. Of moles = 3 × 0.3 × 6.022 × 10^23/6.022 × 10^23
= 0.3 × 3
= 0.9
Hence, the number if moles of the oxygen in 0.3 moles of ozone is 0.9 moles.
Hope ut helps.
Mass of the ozone = 0.3 × 48
= 14.4 g.
Now, Let us first calculate the total no. of atoms in 0.3 mole of ozone.
No. of atoms of O = 3 × 0.3 × 6.022 × 10^23
= 3 × 1.81 × 10^23 atoms.
Now, 3 × 1.81 × 10^23 atoms of oxygen are present in 0.3 moles of Ozone.
Using the formula,
No. Of atoms = No. of moles × Avogadro's number
Thus,
No. Of moles = 3 × 0.3 × 6.022 × 10^23/6.022 × 10^23
= 0.3 × 3
= 0.9
Hence, the number if moles of the oxygen in 0.3 moles of ozone is 0.9 moles.
Hope ut helps.
sknayak:
thanks a lot!!
Answered by
11
We know that 1 mole = 6.02 * 10^23.
We know that Ozone formula is O3, that means it contains 3 oxygen atoms.
So, 1 mole of ozone = 3 * 6.02 * 10^23.
= 1.806 * 10^24 atoms.
Given 0.3 moles of ozone = 3 * 0.3 * 6.02 * 10^23
= 5.41800* 10^23
We know that Number of moles = Number of atoms/6.02 * 10^23
= > 5.41800 * 10^23/6.02 * 10^23
= > 0.9.
Therefore, the number of moles present in 0.3 moles of ozone = 0.9.
Hope it helps!
We know that Ozone formula is O3, that means it contains 3 oxygen atoms.
So, 1 mole of ozone = 3 * 6.02 * 10^23.
= 1.806 * 10^24 atoms.
Given 0.3 moles of ozone = 3 * 0.3 * 6.02 * 10^23
= 5.41800* 10^23
We know that Number of moles = Number of atoms/6.02 * 10^23
= > 5.41800 * 10^23/6.02 * 10^23
= > 0.9.
Therefore, the number of moles present in 0.3 moles of ozone = 0.9.
Hope it helps!
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