Question

number of orbitals required to place all electrons of an element with atomic number 30​

Answer 1

Answer:

Explanation:

In ground state, total number of electrons is equal to it’s atomic number. So the atom (mentioned) has 30 electrons.

So it's configuration will be 1s22s22p63s23p64s23d10

In each subshell (including s), there will be one orbital having m=0 which contains two electrons.

Thus total number of subshells here is 7. So there are 7 orbitals with m=0 and each having 2 electrons.

So total number of electrons with m=0 is 14.

Answer 2

Concept:

The areas surrounding the nucleus in three dimensions known as atomic orbitals are where an electron has the maximum chance of being found. The molecule orbitals are created by combining the atomic orbitals. In quantum chemistry, we have orbitals that are composed of s, p, d, and f subshells.

Given:

Atomic number = 30

Find:

Calculate the number of orbitals required to place all electrons of an element with atomic number 30​.

Solution:

An element with atomic number 30 possesses 30 electrons.

There are 4 orbitals used for the filling of electrons i.e., s, p, d, and f.

The orbitals on the basis of filling of electrons for 30 electrons are as follows: 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s²

The name of the element with atomic number 30 is zinc.

It belongs to transition series elements.

The number of orbitals required to fill 30 electrons is 7.

Hence, the number of orbitals required to place all electrons of an element with atomic number 30​ is seven (7).

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