Question

Number of oxygen atoms present in 22 grams CO2 is

Answer 1

Answer:

Number of oxygen atoms present in 22 g of $CO_{2}$ is $6.022*10^{23}$.

Explanation:

Given mass of $CO_{2}$ = 22 g

Molar mass of $CO_{2}$ = (1×12) + (2×16)

                                = 44 g/mol

Number of moles = given mass ÷ molar mass

                             = $\frac{22}{44}$

                             = 0.5 moles

1 mole of $CO_{2}$ contains $6.022*10^{23}$ molecules

0.5 moles of $CO_{2}$ contains $0.5*6.022*10^{23}$ molecules

                                           = $3.011*10^{23}$ molecules

1 mole of $CO_{2}$ contains 2 oxygen atoms

∴0.5 moles of $CO_{2}$ contains $2*3.011*10^{23}$ oxygen atoms

                                             = $6.022*10^{23}$ oxygen atoms

Answer 2

Answer:

Number of oxygen atoms present in 22 grams CO2 is 6.022 x 10^23 atoms

Explanation:

1 mole of CO2 = 44 g

? moles of CO2 = 22g

22/44 = 0.5 moles of CO2

1 mole of CO2 has 2 moles of Oxygen atoms

0.5 moles of CO2 has ? Moles of Oxygen atoms

0.5 x 2 = 1 mole of Oxygen atoms

1 mole of Oxygen atoms = 6.022 x 10^23 atoms