Question

number of real roots of equation( x^2 +3x +2)^2 - 8(x^2 + 3x ) = 4
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Answer 1

Answer:

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Answer 2

Answer:

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Step-by-step explanation:

refer Given equation:

x  

2

−3∣x∣+2=0

When x>0, we have

x  

2

−3x+2=0

⇒(x−2)(x−1)=0

⇒x=2 or x=1

and when x<0,

x  

2

+3x+2=0

or, (x+2)(x+1)=0

or, x=−2 or x=−1

Therefore, number of real roots is 4.