Math, asked by siddharthchanakya123, 10 months ago

Number of real soln of 6^x+1=8^x-27^(x-1)

Answers

Answered by khanily23

Answer:

Step-by-step explanation:

theorem: Let a,b,c,d be real numbers such that 0<a<b≤c<d. ... If you make a plot of the function f(x)=27x−1−8x+6x+1, you will notice it has two trivial roots at x=1

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